![]() ![]() The inserters will then take the content of their chest minus the average number of items in each chest and if that number goes above -1, we know it has less than average number of items in it and should operate. What happens is that the combinator figures out the average number of items in each chest, but gives you the negative sum instead. On each inserter, set condition to operate if EVERYTHING >= 0. Input: EACH divided by negative number of chests (if you have 6 chests, it's -6) The combinator should be set up as follows: Using red wire, connect each inserter to its corresponding chest (but not to anything else, one wire each going from inserter to chest). Put down an arithmetic combinator and connect the chest wire to the input side and the inserter wire to the output side. Do the same for the unloading inserters, but do NOT connect them together. I usually don't have both backed up belts and not enough trains incoming.You can average the chest content with everything in the line of chests and only allow the inserter connected to operate if there's less than average items in it.Ĭonnect all chests in the line with green wire. If on the d)-moment there is not enough free space in the chest(s), than it doesn't matter how balanced unload is - anyway the free space in the chest(s) will be backed up and train will wait for the belt to consume enough ore. It will matter only in one and only case:Ī) train unloads and all the chests are full ī) train leaves and belt slowly consumes ores from one chest only.Ĭ) that chest has space enough to unload whole train (it will take some time).ĭ) train comes in and contains ore that can be fit into free chest space. When the belt is backed up my design will fill it (and thus unload the train) as fast as the belt is consuming. Then the train will be unloaded slower too, be the belt full or not. That's much better than having proportional unloading but having belt not compressed. It will not be faster with balanced unload anyway - the bottleneck is always in consumption. So, I don't really care about how fast the train unloads if belts and chests are full. Mrvn wrote:I see 2 problems with unbalanced chests.ġ) only a few inserters are unloading the train slowing that down.Ģ) full belts at the start but then some chests run dry and the rest aren't enough to fill the beltġ) that's only when the belt is backed up and slow, and chests are almost full. This still relies even more on the faster belts for compacting the gaps away but I found this prevents alternating between one and all others inserters if you connect to the belts in the right distance from the inserters. Set the belts to report and hold the item count and the inserters to work when item count = 0. What might also help is to connect the inserters to the belts after where the inserters drop things. That way items clear faster from the inserters and then get compacted where the belt gets slower. Use the same setup as before but use faster belts for the start. Or all 6 filling the belt but balanced so they all run dry at about the same time.īut here is an improvemt design that might give you both the maximum throughput and balancing. What you want instead is 3 inserters filling the belt nearly full and then the other 3 inserters filling the belt nearly full. Then the first 4 buffer chests run dry and the remaining 2 inserters place items on the belt on their own, at half the speed. With other setups you get for example 4 inserters dropping items on the belt at full speed filling the belt as fast as it clears while 2 inserters are blocked. It doesn't fill even one red belt from 6 fast inserters. LazyLoneLion wrote:more than that - circuit unload is slower too. 3 fast inserters will have one lane full, so, for six inserters I have two belts braided. ![]() * I use an underground belt to get both lanes working and decrease belt bandwidth overload. Just connect the coal-inserter with the chest in question with a wire, and put the condition "Work only if everything is below 40". There is a simple logic circuit for that. If there happens to be no wood available, the coal will be loaded instead (until the wood will come again). Just let your drones bring 100 wood per requester chest. Usually, I have lots of spare wood - I use it as a fuel. * I fuel my trains on the unloading stations. * I really like that I could squeeze lane-balancer into the design. ![]()
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